What is the purpose of the end parameter in Python’s print() function, especially in loops? [duplicate]

Check the reference page of print. By default there is a newline character appended to the item being printed (end='\n'), and end='' is used to make it printed on the same line.

And print() prints an empty newline, which is necessary to keep on printing on the next line.

EDITED: added an example.
Actually you could also use this:

def a(n): print('*' * n) for i in range(n - 2): print('*' + ' ' * (n - 2) + '*') if n > 1: print('*' * n)

In Python 3.x, the end=' ' is used to place a space after the displayed string instead of a newline.

please refer this for a further explanation.

print() uses some separator when it has more than one parameter. In your code you have 3 ("" is first, ''(n-2) - second, "*" -third). If you don't want to use separator between them add sep='' as key-word parameter.

print("*", ' '*(n-2), "*", sep='')

spam = ['apples', 'bananas', 'tofu', 'cats'] i = 0 for i in range(len (spam)): if i == len(spam) -1: print ('and', spam[i]) elif i == len (spam) -2: print (spam [i], end=' ') else: print (spam [i], end=', ')

So I'm new to this whole coding thing, but I came up with this code. It's probably not as sophisticated as the other stuff, but it does the job.

spam = ['apples', 'bananas', 'tofu', 'cats'] def fruits(): i = 0 while i != len(spam): if len(spam) != i : print ('and', spam[i]) i += 1 fruits()

try this!

use this to understand

for i in range(0,52): print(5*"fiof" ,end=" ")

just put different things here in end and also use with sep

spam=['apples','bananas','tofu','cats'] def fruits(): i=0 while (i<len(spam)): if(i!=(len(spam)-1)): print(spam[i],end=', ') else: print("and",spam[i]) i=i+1 fruits()